70=-5(x^2-4x-10)

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Solution for 70=-5(x^2-4x-10) equation: 



70=-5(x^2-4x-10)

We move all terms to the left:

70-(-5(x^2-4x-10))=0



We calculate terms in parentheses: -(-5(x^2-4x-10)), so:

-5(x^2-4x-10)

We multiply parentheses

-5x^2+20x+50

Back to the equation:

-(-5x^2+20x+50)



We get rid of parentheses

5x^2-20x-50+70=0

We add all the numbers together, and all the variables

5x^2-20x+20=0

a = 5; b = -20; c = +20;
Δ = b2-4ac
Δ = -202-4·5·20
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{10}=2$

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